64-(4(K^2+1)*7)=0

Solution for 64-(4(K^2+1)*7)=0 equation:

Simplifying
64 + -1(4(K2 + 1) * 7) = 0

Reorder the terms:
64 + -1(4(1 + K2) * 7) = 0

Reorder the terms for easier multiplication:
64 + -1(4 * 7(1 + K2)) = 0

Multiply 4 * 7
64 + -1(28(1 + K2)) = 0
64 + -1((1 * 28 + K2 * 28)) = 0
64 + -1((28 + 28K2)) = 0
64 + (28 * -1 + 28K2 * -1) = 0
64 + (-28 + -28K2) = 0

Combine like terms: 64 + -28 = 36
36 + -28K2 = 0

Solving
36 + -28K2 = 0

Solving for variable 'K'.

Move all terms containing K to the left, all other terms to the right.

Add '-36' to each side of the equation.
36 + -36 + -28K2 = 0 + -36

Combine like terms: 36 + -36 = 0
0 + -28K2 = 0 + -36
-28K2 = 0 + -36

Combine like terms: 0 + -36 = -36
-28K2 = -36

Divide each side by '-28'.
K2 = 1.285714286

Simplifying
K2 = 1.285714286

Take the square root of each side:
K = {-1.133893419, 1.133893419}